# Hard SAT Math Question 31 — Video Explanation | 1600.now

Source: https://1600.now/hard/31

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31

$26x^2 + bx = -ax^2 - 8x + 78$  
In the given equation, $b$ and $a$ are constants. The product of the solutions to the equation is $-\frac{78}{a-p}$, where $p$ is a constant. What is the value of $p$?