# Hard SAT Math Question 17 — Video Explanation | 1600.now

Source: https://1600.now/hard/17

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17

The graph of the given equation forms a circle in the $xy$-plane. What point lies on this circle?  
$(x-3)^2 + (y+14)^2 = 49$

A

$(\sqrt{48} + 3,\ -15)$

B

$(\sqrt{48} - 3,\ -7)$

C

$(3,\ -14)$

D

$(-3,\ 14)$